A quadratic equation ax² + bx +c has roots α & β so (x – α)(x - β)=0 implies that
α + β = - b//a and αβ = c/a.
A related equation (x – α’)(x - β’) = 0 has a different combination of {a,b,c} in its coefficients.
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Example: If 6x² - 11x - 7 has roots α & β find the related equation with roots 1/α and 1/β.
From the given equation, the sum of the roots is α + β = 11/6, and the product is αβ = 7/6
For the new equation α’ + β’ = 1/ α + 1/β = (α+β) / αβ =11/7 and α’β’ = 1/αβ = 6/7
The new equation needs the sum of the roots, α’+ β’, now seen to be 11/7, and the product, α’’β’, seen to be 6/7. Rewrite the equation with integer coefficients.
So the new equation is 7x² – 11x + 6 =0; this special case swaps the coefficients.
Exercise:
1 6x² – 11x +1 = 0; new eqn α² , β²
2 6x² – 11x +1 = 0; new eqn α³ , β³
3 5x² – 13x +7 = 0; new eqn α⁻² , β⁻²
4 2x² + 19 x - 6 = 0; new eqn α² + β² , α² - β²
5 3x² – 5 x + 6 = 0; new eqn α + 2β, β+2α
6 6x² – 26x + 24 = 0 new eqn αβ, 1/αβ
7 4x² + 7x - 36 = 0; new eqn β-α, α-β
8 x³ + 4x² + 7x -+ 6 = 0; new eqn 1/α, 1/β. 1/∂
9 4x³ + 4x² + 7x - 3 = 0; new eqn α+β, β+∂, ∂+α
10 2x³ + 4x² + 27x - 36 = 0; new eqn α² - β² , 2αβ
Syllabus quote (2013?) probably Edexcel Further Pure Maths, a Y11 course that year.
Polynomials and Rational functions
Recall and use the relations between the roots and coefficients of polynomial equations of degree 2, 3 and 4 only
Use a given simple substitution to obtain an equation whose roots are related in a simple way to those of the original equation
Sketch graphs of simple rational functions, including the determination of oblique asymptotes, in cases where the degree of the numerator and denominator are at most 2 (detailed plots not required, but sketches are expected to show significant features, such as turning points, asymptotes and intersections with the axes)
See also the page Roots of Equations, adjacent.